3n^2+5n=n^2-7n-18

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Solution for 3n^2+5n=n^2-7n-18 equation: 



3n^2+5n=n^2-7n-18

We move all terms to the left:

3n^2+5n-(n^2-7n-18)=0

We get rid of parentheses

3n^2-n^2+5n+7n+18=0

We add all the numbers together, and all the variables

2n^2+12n+18=0

a = 2; b = 12; c = +18;
Δ = b2-4ac
Δ = 122-4·2·18
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{-12}{4}=-3$

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